(4/a-2)+(5/a+2)=(5/a^2-4)

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Solution for (4/a-2)+(5/a+2)=(5/a^2-4) equation: 


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

4/a+5/a-2+2 = 5/(a^2)-4 // - 5/(a^2)-4

4/a+5/a-(5/(a^2))-2+2+4 = 0

4/a+5/a-5*a^-2-2+2+4 = 0

9*a^-1-5*a^-2+4 = 0

t_1 = a^-1

9*t_1^1-5*t_1^2+4 = 0

9*t_1-5*t_1^2+4 = 0

DELTA = 9^2-(-5*4*4)

DELTA = 161

DELTA > 0

t_1 = (161^(1/2)-9)/(-5*2) or t_1 = (-161^(1/2)-9)/(-5*2)

t_1 = (161^(1/2)-9)/(-10) or t_1 = (161^(1/2)+9)/10

t_1 = (161^(1/2)-9)/(-10)

a^-1-((161^(1/2)-9)/(-10)) = 0

1*a^-1 = (161^(1/2)-9)/(-10) // : 1

a^-1 = (161^(1/2)-9)/(-10)

-1 < 0

1/(a^1) = (161^(1/2)-9)/(-10) // * a^1

1 = ((161^(1/2)-9)/(-10))*a^1 // : (161^(1/2)-9)/(-10)

-10*(161^(1/2)-9)^-1 = a^1

a = -10*(161^(1/2)-9)^-1

t_1 = (161^(1/2)+9)/10

a^-1-((161^(1/2)+9)/10) = 0

1*a^-1 = (161^(1/2)+9)/10 // : 1

a^-1 = (161^(1/2)+9)/10

-1 < 0

1/(a^1) = (161^(1/2)+9)/10 // * a^1

1 = ((161^(1/2)+9)/10)*a^1 // : (161^(1/2)+9)/10

10*(161^(1/2)+9)^-1 = a^1

a = 10*(161^(1/2)+9)^-1

a in { -10*(161^(1/2)-9)^-1, 10*(161^(1/2)+9)^-1 }

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